wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The digits of a two digit number differ by 2. If the digits are interchanged and resulting number is added to the original number we get 88.

What is the original number?


A

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

42

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

57

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

53

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

53


Given : The difference between the digits is 2.

So, if unit's place digit is x then ten’s place will be x + 2,then the number will be 10(x + 2) + x.

After reversing the digit the number will be 10x + x + 2.

10(x + 2) + x + 10x + x + 2 = 88 (given)

10x + 20 + x + 10x + x + 2 = 88

22x + 22 = 88

22x = 88 - 22 = 66

x = 66 ÷ 22 = 3

The number is 53.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Numbers and Letters
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon