Question

The dimensional formula for inductance is

• A. ML²TA^-2
• B. ML²T^-2A^-2
• C. ML²T^-2A^-1
• D. ML²T^-1A^-2

Answer 1

The correct option is B

ML²T^-2A^-2

$e=-L\frac{di}{dt}L=e\frac{dt}{di}L=\frac{V.sec}{amp}\Rightarrow L=\frac{\left(M{L}^2{T}^{-2}\right)\left(T\right)}{\left(AT\right)\left(A\right)}Where,V=\frac{W}{q}=\frac{M{L}^2{T}^{-2}}{AT}L=\left[M{L}^2{T}^{-2}{A}^{-2}\right]Sec=TAmpere=A$