Question

The dimensional formula of the magnetic field $\left(B\right)$ is -

• A. $\left[M^1{L}^0{T}^2{A}^{-1}\right]$
• B. $\left[M^1{L}^0{T}^{-2}{A}^{-1}\right]$
• C. $\left[M^1{L}^0{T}^2{A}^1\right]$
• D. $\left[M^1{L}^0{T}^{-2}{A}^1\right]$

Answer 1

The correct option is B $\left[M^1{L}^0{T}^{-2}{A}^{-1}\right]$

We know that,

$\text{Magnetic Field}=\frac{\text{Force}}{\text{Charge}\times \text{Velocity}}$

Now, substituting them in dimensional form,

$\left[B\right]=\frac{\left[M^1{L}^1{T}^{-2}\right]}{\left[A^1{T}^1\right]\times \left[L^1{T}^{-1}\right]}$

$\Rightarrow \left[B\right]=\left[M^1{L}^0{T}^{-2}{A}^{-1}\right]$