the diogonals of a rhombus are of measurement 12 CM and 16cm. Find the length of side of the rhombus.

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Solution

In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
BD=16cm

half of AC=AO
half of 12cm=A0
AO=6cm

half of BD=OD
half of 16cm=OD
OD=8cm

AD=side of rhombus ABCD
side²=AO² + OD²(pytha. theorum)
side²=6²+ 8²
side²=36 + 64
side²=100
side²=10²
side=10cm

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