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Question

the diogonals of a rhombus are of measurement 12 CM and 16cm. Find the length of side of the rhombus.

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Solution

In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
​BD=16cm

half of AC=AO
half of 12cm=A0
​AO=6cm

half of BD=OD
half of 16cm=OD
OD=8cm

AD=side of rhombus ABCD
side2=AO​2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm


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