The dipole moment of each molecule of a paramagnetic gas is 1.5×10−23amp×m2.The temperature of gas is 27∘C and the number of molecules per unit volume in it is 2×1026m−3. The maximum possible intensity of magnetisation in the gas will be
A
3×103amp/m
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B
4×10−3amp/m
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C
5×10−5amp/m
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D
6×10−4amp/m
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Solution
The correct option is A3×103amp/m I=MV=μNV=1.5×10−23×10261=3×103Amp/m