Question

The dipole moment of each molecule of a paramagnetic gas is $1.5\times {10}^{-23}amp\times m^2$. The temperature of gas is ${27}^{\circ }$ C and the number of molecules per unit volume in it is $2\times {10}^{26}{m}^{–3}$. The maximum possible intensity of magnetisation in the gas will be

• A. $3\times {10}^{3}amp/m$
  
• B. $4\times {10}^{-3}amp/m$
  
• C. $5\times {10}^{5}amp/m$
  
• D. $6\times {10}^{-4}amp/m$
  

Answer 1

The correct option is A $3\times {10}^{3}amp/m$


$I=\frac{M}{V}=\frac{\mu N}{V}=\frac{1.5\times {10}^{-23}\times 2\times {10}^{26}}{1}=3\times {10}^{3}amp/m$