wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The dipper in a ripple tank vibrates at a frequency of 4.0Hz and the resulting wave pattern is photographed. The distance between the two crests shown is 20cm. What is the speed of the wave ?

313868.png

A
4cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16cms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
20cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 16cms1
Answer is C.

The relationship between the speed (v) of a wave and its wavelength (λ) and frequency (f) is given as follows.
The equation is speed = wavelength * frequency. That is, v=λ×f
In this case, the frequency is 4 Hz and the wavelength is 20 cm/5 as the distance of 5 crests and 5 troughs are given as 20 cm.
Therefore, v = 4 * 4 = 16 cm/s.
Hence, the speed of the wave is 16 cm/s.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Characteristics of Sound Waves
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon