The displacement from mean position of a particle in SHM at 3 seconds is -3-2 of the amplitude- Its time period will be

The correct option is A 18 sec Let equation ⇒ y = a sin(wt)at t = 3, y = √(3)/2a so, sin (w× 3) = √(3)/2 so, 3w = π/3 w = π /9 ...

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Standard XII

Physics

Kinetic Energy Formulae

The displacem...

Question

The displacement from mean position of a particle in SHM at $3$ seconds is $\sqrt{3} / 2$ of the amplitude. Its time period will be

18 s e c

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6 \sqrt{3} s e c

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9 s e c

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3 \sqrt{3} s e c

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Solution

The correct option is A $18 s e c$
Let equation $\Rightarrow$
y = a sin(wt)
at t = 3, y = $\frac{\sqrt{3}}{2} a$
so, $s i n (w \times 3) = \frac{\sqrt{3}}{2}$
so, $3 w = \frac{π}{3}$
$w = π / 9$
$T = \frac{2 π}{w} = 18$ second
Option (A)

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The displacement from mean position of a particle in SHM at 3 seconds is √3/2 of the amplitude. Its time period will be

The correct option is A 18 secLet equation ⇒y = a sin(wt)at t = 3, y =√32aso, sin(w×3)=√32so, 3w=π3w=π/9T=2πw=18 secondOption (A)

The displacement from mean position of a particle in SHM at $3$ seconds is $\sqrt{3} / 2$ of the amplitude. Its time period will be

The correct option is A $18 s e c$
Let equation $\Rightarrow$
y = a sin(wt)
at t = 3, y = $\frac{\sqrt{3}}{2} a$
so, $s i n (w \times 3) = \frac{\sqrt{3}}{2}$
so, $3 w = \frac{π}{3}$
$w = π / 9$
$T = \frac{2 π}{w} = 18$ second
Option (A)