The displacement of a particle executing SMH is given by x-0-01 sin 100-t-0-05- The time period is

The correct option is D 0.02 secGiven, Angular frequency (ω) = 100π So, Time period = 2πω = 2 π100 π = 0.02 sec Therefore, B is correct option. ...

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Standard XII

Physics

Wave Equation

The displacem...

Question

The displacement of a particle executing SMH is given by $x = 0.01 s i n 100 π (t + 0.05) .$ The time period is

0.01

sec

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0.02

sec

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0.1

sec

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0.2

sec

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Solution

The correct option is D $0.02$ sec
Given, Angular frequency $(ω) = 100 π$

So, Time period $= \frac{2 π}{ω} = \frac{2 π}{100 π} = 0.02 s e c$

Therefore, B is correct option.

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The displacement of a particle executing SMH is given by x=0.01sin100π(t+0.05). The time period is

The correct option is D 0.02secGiven, Angular frequency (ω)=100πSo, Time period =2πω=2π100π=0.02secTherefore, B is correct option.

The displacement of a particle executing SMH is given by $x = 0.01 s i n 100 π (t + 0.05) .$ The time period is

The correct option is D $0.02$ sec
Given, Angular frequency $(ω) = 100 π$

So, Time period $= \frac{2 π}{ω} = \frac{2 π}{100 π} = 0.02 s e c$

Therefore, B is correct option.