The displacement of $S$ of a particle at time $t (O < t < π$ ) is given by $S = sin 2 t - 6 cos t$ . Then the acceleration for the value of $t$ for which its velocity is zero is

0 u n i t / {sec}^{2}

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3 u n i t / {sec}^{2}

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2 u n i t / {sec}^{2}

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4 u n i t / {sec}^{2}

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Solution

The correct option is A $0 u n i t / {sec}^{2}$
$\begin{matrix} S = sin 2 t - 6 cos t V = \frac{d s}{d r} = Z cos z t + 6 sin t a = \frac{d v}{d t} = - 4 sin 2 t + 6 cos t V = 0 a t 2 cos 2 t + 6 sin t = 0 t = - 0.284 r a d i a n a t = - 0.284 a w i l l b e e q u a l t o z e r o . A n s . \end{matrix}$

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The displacement of S of a particle at time t(O<t<π) is given by S=sin2t−6cost. Then the acceleration for the value of t for which its velocity is zero is

The correct option is A 0 unit/sec2S=sin2t−6costV=dsdr=Zcoszt+6sinta=dvdt=−4sin2t+6costV=0at2cos2t+6sint=0t=−0.284radianat=−0.284awillbeequaltozero.Ans.

The displacement of $S$ of a particle at time $t (O < t < π$ ) is given by $S = sin 2 t - 6 cos t$ . Then the acceleration for the value of $t$ for which its velocity is zero is