The displacement of the particle is given by x=2t3−6t in m. The acceleration of the particle at 2sec is
A
36m/s2
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B
24m/s2
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C
12m/s2
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D
20m/s2
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Solution
The correct option is B24m/s2 As we know that the acceleration of the particle is given by a=dvdt and also, v=dxdt Given, x=2t3−6t So, v=dxdt=d(2t3−6t)dt ⇒v=6t2−6 also, a=dvdt=d(6t2−6)dt=12t Thus, the acceleration of the particle is 12×2=24m/s2