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Question

The displacement of the particle is given by x=2t3−6t in m. The acceleration of the particle at 2 sec is

A
36 m/s2
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B
24 m/s2
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C
12 m/s2
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D
20 m/s2
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Solution

The correct option is B 24 m/s2
As we know that the acceleration of the particle is given by
a=dvdt and also, v=dxdt
Given, x=2t36t
So, v=dxdt=d(2t36t)dt
v=6t26
also, a=dvdt=d(6t26)dt=12t
Thus, the acceleration of the particle is 12×2=24 m/s2

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