CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The displacement of the particle is given by x=3t32t2+5 in m. The acceleration of the particle at 4 sec is

A
58 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
62 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
68 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
70 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 68 m/s2
As we know that the acceleration of the particle is given by
a=dvdt and also, v=dxdt
Given, x=3t32t2+5
So, v=dxdt=d(3t32t2+5)dt
v=9t24t
also, a=dvdt=d(9t24t)dt=18t4
Thus, the acceleration of the particle is 18×44=68 m/s2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon