Question

# The displacement of the particle is given by x=2t3−6t in m. The acceleration of the particle at 2 sec is

A
36 m/s2
B
24 m/s2
C
12 m/s2
D
20 m/s2

Solution

## The correct option is B 24 m/s2As we know that the acceleration of the particle is given by  a=dvdt and also, v=dxdt Given, x=2t3−6t So, v=dxdt=d(2t3−6t)dt ⇒ v=6t2−6 also, a=dvdt=d(6t2−6)dt=12t Thus, the acceleration of the particle is 12×2=24 m/s2

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