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Standard XII

Physics

Distance Time Graph

The displacem...

Question

The displacement $(s)$ and time $(t)$ graphs for two moving objects $A$ and $B$ are straight lines inclined at $30^{o}$ with the time axis and $30^{o}$ with the displacement axis respectively. Then what would be their velocity ratio $\frac{V_{A}}{V_{B}} ?$

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Solution

Velocity of $A = tan 30^{o}$
Velocity of $B = tan 60^{o}$
$\frac{V_{A}}{V_{B}} = \frac{tan 30^{o}}{tan 60^{o}} = \frac{\frac{1}{\sqrt{3}}}{\sqrt{3}} = \frac{1}{3}$

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The displacement $(s)$ and time $(t)$ graphs for two moving objects $A$ and $B$ are straight lines inclined at $30^{o}$ with the time axis and $30^{o}$ with the displacement axis respectively. Then what would be their velocity ratio $\frac{V_{A}}{V_{B}} ?$

Velocity of $A = tan 30^{o}$
Velocity of $B = tan 60^{o}$
$\frac{V_{A}}{V_{B}} = \frac{tan 30^{o}}{tan 60^{o}} = \frac{\frac{1}{\sqrt{3}}}{\sqrt{3}} = \frac{1}{3}$