The displacement (x) of a particle along a straight line at time t is given by x=a0+a12t+a23t2, the acceleration of the particle is
A
a1/2
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B
a2/3
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C
a0+a2/3
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D
2a2/3
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Solution
The correct option is D2a2/3 x=(a0+a12t+a23t2)
We know that v=dxdt ⇒v=ddt(a0+a12t+a23t2)
Or v=a12+a23×2t=a12+2a23t
Acceleration, a=dvdt =ddt(a12+2a23t)=2a23