The displacement (x) of a particle as a function of time (t) is given by X = a sin (bt + c) Where a, b and c are constants of motion. Choose the correct statement(s) from the following
A
The motion repeats itself in a time interval
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The energy of the particle remains constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The velocity of the particle is zero at x =
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
The acceleration of the particle is zero at x =
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A The motion repeats itself in a time interval The motion of the particle is simple harmonic. The displacement at time t is X = a sin (bt+c)∴ Displacement at time (t+2πb) is x(att+2πb)=asin[b(t+2πb)+c]=asin(bt+c+2π)=asin(bt+c)=xattimet Hence statement (a) is correct. Statement (b) is also correct since the same displacement is recovered after a time interval of 2πb .Statement (c) is correct because the velocity is zero when the displacement = ± the amplitude, i.e. at the extreme ends of the motion. Statement (d)is incorrect, the acceleration is maximum (in magnitude) at x = ± a.