Question

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation t = $\sqrt{x}$ + 3, where x is in meter and t is in second. Find the displacement of the particle when its velocity is zero.

• A. $zero$
• B. $12m$
• C. $6m$
• D. $18m$

Answer 1

The correct option is A $zero$

$t=\sqrt{x}+3$

$1=\frac{1}{2\sqrt{x}}\frac{dx}{dt}+0$

$\frac{dx}{dt}=2\sqrt{x}$

So, when $v=0$

$x=0$