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Question

The dissociation constant of 0.01M CH3COOH is 1.8×105 then calculate CH3COO concentration in 0.1M HCl solution.

A
1.8×106 molL1
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B
1.8×104 molL1
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C
2.8×106 molL1
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D
2.4×104 molL1
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Solution

The correct option is A 1.8×106 molL1
CH3COOHCH3COO + H+ HClCl+H+ Common ionCH3COOHCH3COO+H+0.01 0 00.01x x 0.1+x
Here x is very small value so x can be neglect.
1+x=0.1
Ka=[CH3COO][H+][CH3COOH][CH3COO]=1.8×105×0.010.1[CH3COO]=1.8×106 molL1

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