The dissociation constants for acetic acid and HCN at 25oC are 1.5×10−5 and 4.5×10−10, respectively. The equilibrium constant for the equilibrium will be: CN−+CH3COOH⇌HCN+CH3COO−
A
3.0×105
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B
3.0×10−5
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C
3.0×10−4
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D
3.0×104
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Solution
The correct option is D3.0×104 CH3COOH=HCN+CH3COO−
Ka=1.5×10−5 .....(1)
HCN=H++CN−;Ka1=4.5×10−10 ......(2)
CN−+CH3COOH=HCN+CH3COOH−
K = ?
On subtracting equation (2) from equation (1) we get
K=Ka/Ka1=1.5×10−54.5×10−10=1053=3.33×104
So option D is correct.