The distance between points (a+b,b+c) and (a–b,c–b) is :
2√(a2 + b2)
2√(b2 + c2)
2√(2) b
√(a2- c2)
A(a+b,b+c) and B(a−b,c−b)
Using the distsnce between two points formula we get
AB2 = (a+b−a+b)2 + (b+c−c+b)2 = 4b2 + 4b2 = 8b2 AB=2√2b
a2 + b2 + c2 - ab - bc - ca equals:
The length of the perpendicular drawn from the point P(a, b, c) from z-axis is
Find: (a+b+c)×(a+b−c)=
The distance between the points (a, b) and (– a, – b) is: