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Question

The distance between points (a + b, b + c) and (a – b, c – b) is ____ units.

A
2a2+b2
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B
2b2+c2
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C
22b
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D
2a2+c2
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Solution

The correct option is C 22b
Distance between points (x1,y1) and (x2,y2) = (x2x1)2+(y2y1)2

Let's name the points as A(a + b, b + c) and B(a - b, c - b) .

AB = (x2x1)2+(y2y1)2

AB2= (a+b(ab))2+(b+c(cb))2

AB2=4b2+4b2=8b2

AB=22b

Therefore, the distance between points (a + b, b + c) and (a – b, c – b) is 22b units.

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