Question

The distance between the point (1, 2) and a point on the line x+y = 6 is 3 units. The coordinates of the point is

• A. (3,3)
• B. (5,1)
• C. (4,2)
• D. (-1,7)
• E. (1,3)

Answer 1

The correct option is C

(4,2)

Any point on the given line can be taken as (x, 6-x) Given that the distance between the points is 3 units

Distance formula = $\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

Using both the relations we get the coordinates as (4, 2) and (1, 5).