The distance between the points $(- 4, 7)$ and $(1, - 5)$ is

\sqrt{13}

units

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13

units

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\sqrt{14}

units

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14

units

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Solution

The correct option is B $13$ units
Distance between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ can be calculated using the formula-
$= \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$
Distance between $(- 4, 7)$ and $(1, - 5)$
$= \sqrt{{(1 - (- 4))}^{2} + {(- 5 - 7)}^{2}} = \sqrt{25 + 144}$
$= \sqrt{169} = 13 u n i t s$

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Similar questions

The distance between the points (–4, 7) and (1, –5) is ___ units.

A B : B C = 5 : 13

A C = 14

B C =

If the distance between points (p, –5) and (2, 7) is 13 units, then p is _____________

11^{1} + 12^{2} + 13^{3} + 14^{4} + 15^{5} + 16^{6} .

(11^{1} + 12^{2} + 13^{3} + 14^{4} + 15^{5} + 16^{6})

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