The distance between the points (a, b) and (– a, – b) is :
a2 + b2
√(a2 + b2)
0
2√(a2 + b2)
By using distance formula
d = √(a−(−a))2+(b−(−b))2
= √(2a)2+(2b)2
d = 2√a2+b2
(a,b) is the mid point of the chord ¯AB of the circle x2+y2=r2. The tangent at A,B meet a C. then area of ΔABC
If (1+i)(1+2i)(1+3i)....(1ni)=a+ib, then 2×5×10×....×(1+n2) is equal to
The equation of the circle with center (– a, – b) and radius √a2 – b2 is:
Simplify: (a−b)2+4ab