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Question

The distance between the points P(1,1) and Q(5,7) is ........................

A
11
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B
10
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C
5
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D
7
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Solution

The correct option is B 10
Distance =(x2x1)2+(y2y1)2
=[5(1)]2+[71]2
=62+82
=100=10 units

1185892_1349631_ans_b5fa635a26904d45abeb376c2b969bc8.jpg

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