The distance between the straight lines $5 x + 12 y + 11 = 0, 5 x + 12 y + 37 = 0$ is

2

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3

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26

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48

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Solution

The correct option is B $2$
$5 x + 12 y + 11 = 0, 5 x + 12 y + 37 = 0$
Since, these lines are parallel.
So, $d = \frac{| c_{1} - c_{2} |}{\sqrt{a^{2} + b^{2}}}$
$\Rightarrow d = \frac{26}{13} = 2$

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