The distance between the straight lines $7 x + 24 y - 13 = 0, 7 x + 24 y + 12 = 0$ is

1

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2

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25

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50

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Solution

The correct option is A $1$
Given equation of lines are
$7 x + 24 y - 13 = 0, 7 x + 24 y + 12 = 0$
Since, the lines are parallel,
So, $d = \frac{| c_{1} - c_{2} |}{\sqrt{a^{2} + b^{2}}}$
$d = \frac{25}{25} = 1$

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