The distance between the two points is $5.$ One of them is $(3, 2)$ and the ordinate of the second is $- 1$ , then find sum of its x-coordinate.

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Solution

Using distance formula:
$\sqrt{(3 - x)^{2} + (2 + 1)^{2}}$
$\Rightarrow (3 - x)^{2} + 9 = 25$
$\Rightarrow 9 + x^{2} - 6 x + 9 - 25 = 0$
$\Rightarrow x^{2} - 6 x - 7 = 0$
$\Rightarrow x = 7, - 1$

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The distance between the two points is 5. One of them is (3,2) and the ordinate of the second is −1 , then find sum of its x-coordinate.

Using distance formula:√(3−x)2+(2+1)2⇒(3−x)2+9=25⇒9+x2−6x+9−25=0⇒x2−6x−7=0⇒x=7,−1

The distance between the two points is $5.$ One of them is $(3, 2)$ and the ordinate of the second is $- 1$ , then find sum of its x-coordinate.

Using distance formula:
$\sqrt{(3 - x)^{2} + (2 + 1)^{2}}$
$\Rightarrow (3 - x)^{2} + 9 = 25$
$\Rightarrow 9 + x^{2} - 6 x + 9 - 25 = 0$
$\Rightarrow x^{2} - 6 x - 7 = 0$
$\Rightarrow x = 7, - 1$