Question

The distance moved by a particle in simple harmonic motion in one time period is

• A. A
• B. 2A
• C. 4A
• D. Zero

Answer 1

The correct option is C 4A

$T=\frac{2\pi }{\omega }$

Time taken to move from mean position to extreme position is

$\omega t=\frac{\pi }{2}$ (as the phase covered is $\frac{\pi }{2}$)

$t=\frac{\pi }{2\omega }$

$t=\frac{T}{4}$

distance covered in time $t$ is $A$

Distance covered in time $T=4A$

as$T=4t$

So correct answer is option C