The distance of $(1, - 2)$ from the common chord of $x^{2} + y^{2} - 5 x + 4 y - 2 = 0$ and
$x^{2} + y^{2} - 2 x + 8 y + 3 = 0$ is

2

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0

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3

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Solution

The correct option is C $0$
$e q^{n}$ of common chord of circle $s_{1}$ and $s_{2}$ is given by
$s_{1} - s_{2} = 0$
$∴ e q^{n}$ of common chord is
$3 x + 4 y + 5 = 0$
distance of $(1, - 2)$ from common chord is
$d = | \frac{3 - 8 + 5}{5} | = 0$
point $(1, - 2)$ lie on $3 x + 4 y + 5 = 0$

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