MyQuestionIcon

6

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Elliptical Orbits and Kepler's Laws

The distance ...

Question

The distance of a planet from the sun is 5 times the distance between the earth and the sun. The time period of revolution of the planet is

A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

According to Kepler’s law,
$T \propto R^{\frac{3}{2}} ∴ T_{p l a n e t} = (5)^{\frac{3}{2}} T_{e a r t h} = 5^{(\frac{3}{2})} \times 1 y e a r = 5^{\frac{3}{2}} y e a r s$

Suggest Corrections

thumbs-up

15

Similar questions

Q. A planet revolves around the sun whose mean distance is

1.588

times the mean distance between earth and sun. The revolution time of planet will be

Q. The distance of a planet from the sun is

5

times the distance between the earth and the sun. The Time period of the planet is:

Q. The distance of planet Jupiter from the Sun is

5.2

times that of the earth. Find the period of revolution of Jupiter around the Sun.

Q. The time of revolution of planet

A

around the sun is 8 times that of another planet

B

. The distance of planet

A

from the sun is how many times greater than that of the planet

B

Q. Distance between a distant planet and the Sun is four times that of distance between Earth and Sun. Calculate the time taken by planet to orbit the Sun in respect of Earth years.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Elliptical Orbits and Kepler's Law Tackle

PHYSICS

Watch in App

explore_more_icon

Explore more

Elliptical Orbits and Kepler's Laws

Standard X Physics

Join BYJU'S Learning Program

CrossIcon