Question

The distance of neptune and saturn from sun are nearly ${10}^{13}$ and ${10}^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

• A. $\sqrt{10}$
• B. 100
• C. $10\sqrt{10}$
• D. $\frac{1}{\sqrt{10}}$

Answer 1

The correct option is C

$10\sqrt{10}$

$\frac{T_1}{T_2}=(\frac{R_1}{R_2}{)}^{\frac{3}{2}}=(\frac{{10}^{13}}{{10}^{12}}{)}^{\frac{3}{2}}=(1000{)}^{\frac{1}{2}}=10\sqrt{10}$