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Standard XIII

Physics

Kepler's Law

The distance ...

Question

The distance of neptune and saturn from sun are nearly $10^{13}$ and $10^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

$\sqrt{10}$

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100

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$10 \sqrt{10}$

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$\frac{1}{\sqrt{10}}$

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Solution

The correct option is C
$10 \sqrt{10}$

$\frac{T_{1}}{T_{2}} = (\frac{R_{1}}{R_{2}})^{\frac{3}{2}} = (\frac{10^{13}}{10^{12}})^{\frac{3}{2}} = (1000)^{\frac{1}{2}} = 10 \sqrt{10}$

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Similar questions

The distance of neptune and saturn from sun are nearly $10^{13}$ and $10^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

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The distance of neptune and saturn from sun are nearly 1013 and 1012 meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

The correct option is C 10√10 T1T2=(R1R2)32=(10131012)32=(1000)12=10√10

The distance of neptune and saturn from sun are nearly $10^{13}$ and $10^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

The correct option is C
$10 \sqrt{10}$

$\frac{T_{1}}{T_{2}} = (\frac{R_{1}}{R_{2}})^{\frac{3}{2}} = (\frac{10^{13}}{10^{12}})^{\frac{3}{2}} = (1000)^{\frac{1}{2}} = 10 \sqrt{10}$