The distance s metres, which a falling body covers in time t seconds is 4.9 times the square of the time t. A stone which is dropped from a cliff top takes 3.5 seconds to reach the base of the cliff. Use this information to calculate the height of the cliff to the nearest metre.

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Solution

$S = 4.9 t^{2}$
If stone which is dropped from a cliff top takes $3.5$ seconds to reach the base of the cliff.
Then $s = 4.9 (3.5)^{2} = 60.025 m$

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The distance s metres, which a falling body covers in time t seconds is 4.9 times the square of the time t. A stone which is dropped from a cliff top takes 3.5 seconds to reach the base of the cliff. Use this information to calculate the height of the cliff to the nearest metre.

S=4.9t2If stone which is dropped from a cliff top takes 3.5 seconds to reach the base of the cliff.Then s=4.9(3.5)2=60.025 m

$S = 4.9 t^{2}$
If stone which is dropped from a cliff top takes $3.5$ seconds to reach the base of the cliff.
Then $s = 4.9 (3.5)^{2} = 60.025 m$