The domain of definition of the function $y (x)$ given by $2^{x} + 2^{y} = 2$ is

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Solution

For domain of $x$ let's assume $y$ as a function of $x :$
so,

$2 - 2^{x} > 0$
$x^{2} < 2$
$x < 1;$

Therefore solution is set form we have
$x ϵ (- \infty, 1)$

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