Question

The dry cell of E.M.F $12V$, is connected in series to a $3\Omega$ and a $6\Omega$ resistor. Calculate the total power supplied by the dry cell.

• A. $9W$
• B. $72W$
• C. $16W$
• D. $2W$

Answer 1

Answer: (C)

$16W$

Equivalent resistance for resistance connected in series is given by

$R_{eq}=R_1+R_2$

Since, in the given case $3\Omega$ and $6\Omega$ are connected in series.

Hence, equivalent resistance, $R_{eq}=3+6=9\Omega$

Given, emf of cell $V=12V$

Hence, the power supplied by the cell is given by, $P=\frac{V^2}{R}$

$P=\frac{12\times 12}{9}=16W$