The dry cell of e-m-f- 12 V- is connected in series to a 3 - and a 6 - resistor- Calculate the total power supplied by the dry cell-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Capacitor in an AC Circuit

The dry cell ...

Question

The dry cell of e.m.f. 12 V, is connected in series to a $3 Ω$ and a $6 Ω$ resistor. Calculate the total power supplied by the dry cell.

9 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

72 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 16 W
Assuming the voltmeters to be ideal, we can calculate the equivalent resistance as:

$R_{e q} = 3 + 6 = 9 Ω$
Hence the power supplied is, $P = \frac{V^{2}}{R_{e q}} = \frac{144}{9} = 16 W a t t s$

Suggest Corrections

Similar questions

Q. The dry cell of E.M.F

12 V

, is connected in series to a

3 Ω

and a

6 Ω

resistor. Calculate the heat energy produced by the

3 Ω

resistor in

5 s

Q. Two resistors of

2 Ω

and

4 Ω

are connected in parallel. Two more resistors

3 Ω

and

6 Ω

are also connected in parallel. These two combinations are in series with a battery of emf

5

V and internal resistance

0.7 Ω

. Calculate the current through

6 Ω

resistor.

A battery of e.m.f. 15 V and internal resistance $3 Ω$ is connected to two resistors $3 Ω$ and $6 Ω$ connected in parallel. Find:

(a) the current through the battery,

(b) the p.d. between the terminals of the battery,

(d) the current in $6 Ω$ resistor.

Q. How many dry cells, each of e.m.f.

1.5 V

and internal resistor

0.5 Ω

must be joined in series with a resistor of

20 Ω

to give a current of

0.6 A

in the circuit?

Q. A battery of internal resistance,

3 Ω

is connected to

20 Ω

resistor and potential difference across the resistor is 10 V. If another resistor of

30 Ω

is connected in series with the first resistor and battery is again connected to the combination calculate the e.m.f. and terminal potential difference across the combination.

Join BYJU'S Learning Program

The dry cell of e.m.f. 12 V, is connected in series to a 3Ω and a 6Ω resistor. Calculate the total power supplied by the dry cell.

The correct option is D 16 WAssuming the voltmeters to be ideal, we can calculate the equivalent resistance as:Req=3+6=9ΩHence the power supplied is, P=V2Req=1449=16 Watts

The dry cell of e.m.f. 12 V, is connected in series to a $3 Ω$ and a $6 Ω$ resistor. Calculate the total power supplied by the dry cell.

The correct option is D 16 W
Assuming the voltmeters to be ideal, we can calculate the equivalent resistance as:

$R_{e q} = 3 + 6 = 9 Ω$
Hence the power supplied is, $P = \frac{V^{2}}{R_{e q}} = \frac{144}{9} = 16 W a t t s$