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Nernst Equation

The E0M3+/M...

Question

The $E_{M^{3 +} / M^{2 +}}^{0}$ values of Cr, Mn, Fe and Co are $- 0.41, + 1.57, + 0.77$ and $+ 1.97 V$ respectively. For which one of these metals the change in oxidation state from $+ 2$ to $+ 3$ is easiest?

C r

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M n

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F e

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C o

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Solution

The correct option is B $C r$
From given reduction potential it can be seen that as $C r$ has the highest oxidation potential (lowest reduction potential) for $+ 2$ to $+ 3$

So, it has the highest tendency to oxidize from $+ 2$ to $+ 3$ .

Option A is correct.

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Similar questions

The $E {^{0}}_{M^{3 +} / M^{2 +}}$ values for Cr, Mn, Fe and Co are -0.41, + 1.57, + 0.77 and + 1.97V respectively.For which one of these metals the change oxidation state from +2 and +3 is easily?

Q. The

_{M^{3 +} / M^{2 +}}^{o}

values for Cr, Mn, Fe and Co are

- 0.41, + 1.57, + 0.77

and

+ 1.97

V respectively. For which one of these metals the change in oxidation state from

+ 2

+ 3

is easiest?

Q. The

E_{M^{3 +} / M^{2 +}}^{o}

values for

C r

M n

F e

and

C o

are

- 0.41

+ 1.57

, +

0.77

and +

1.97

respectively. For which one of following metal the change in oxidation state from +2 to +3 is easiest?

For the four successive transition elements (Cr, Mn, Fe and Co), what is the order of stability of their +2 states?

(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Q. The correct order of

E^{0} M^{2 +} / M

values with negative sign for the four successive elements Cr, Mn, Fe and Co is

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The E0M3+/M2+ values of Cr, Mn, Fe and Co are −0.41, +1.57, +0.77 and +1.97V respectively. For which one of these metals the change in oxidation state from +2 to +3 is easiest?

The correct option is B CrFrom given reduction potential it can be seen that as Cr has the highest oxidation potential (lowest reduction potential) for +2 to +3 So, it has the highest tendency to oxidize from +2 to +3.Option A is correct.

The $E_{M^{3 +} / M^{2 +}}^{0}$ values of Cr, Mn, Fe and Co are $- 0.41, + 1.57, + 0.77$ and $+ 1.97 V$ respectively. For which one of these metals the change in oxidation state from $+ 2$ to $+ 3$ is easiest?

The correct option is B $C r$
From given reduction potential it can be seen that as $C r$ has the highest oxidation potential (lowest reduction potential) for $+ 2$ to $+ 3$

So, it has the highest tendency to oxidize from $+ 2$ to $+ 3$ .

Option A is correct.