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Heat of Formation

The E ∘ at 2...

Question

The E $^{\circ}$ at 25 $^{\circ}$ C for the following reaction at the indicated concentration is 1.50 V. Calculate the $Δ$ G in kJ at 25 $^{\circ}$ C : $C r (s) + 3 A g^{+} (a q, 0.1 M) \to A g (s) + C r^{3 +} (a q, 0.1 M)$

-140.94

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-295

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-212

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-422.83 kJ

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Solution

The correct option is D -422.83 kJ
$Δ G = Δ G^{\circ} + R T l n Q$
$\Rightarrow$ $- n f E^{\circ} + 2.303 R T l o g \frac{[C r^{3 +}]}{[A g^{+}]^{3}}$
$Δ G = - 3 \times 96500 \times 1.50 + 8.314 \times 298 \times 2.303 l o g \frac{(0.1)}{(0.1)^{3}}$
$\Rightarrow$ $- 422838.3 J$ or $- 422.83 k J$

Hence option (D) is correct.

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Similar questions

1.5 V

E_{cell}^{\circ} in V

C r (s) + 3 A g^{+} (a q, 0.1 M) \to 3 A g (s) + C r^{3 +} (a q, 0.1 M)

E^{\circ}

25^{\circ} C

0.22 V

25^{\circ} C

H_{2} (g) + 2 A g C l (s) \to 2 A g (s) + 2 H C l (a q)

3 C r^{2 +} (a q, 1 M) \to 2 C r^{3 +} (a q, 1 M) + C r (s)

Δ

Δ

25^{\circ}

E_{C r^{3 +} (a q) / C r (a q)} = 0.5 V E_{C r^{3 +} (a q) / C r^{2 +} (a q)} = - 0.41 V

Δ

35^{\circ} C = - 270.50 k J

25^{\circ} C

A g (s) | A g^{+} (a q, 10^{- 5} M); E_{A g^{+} / A g}^{0} = - 0.80 V

Δ G^{\circ}

C u_{(a q)}^{2 +} + 2 A g_{(s)} \to C u_{(s)} + 2 A g_{(a q)}^{+}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{A g / A g^{+}}^{0} = - 0.8 V

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