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Cells

The e.m.f. of...

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The e.m.f. of a Daniell cell at 298 K is E1. Zn/SO4(0.01 M) || CuSO4(1.0 M)/Cu When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. is changed to E2. What is the relationship betweenE1 and E2 : (1) E1 > E2 (2) E1 < E2 (3) E1 = E2 (4) E2 = 0 E1

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Q. The emf of a Daniel cell at 298 K is

E_{1}

concentration of

Z n S O_{4}

is 0.1 M and that

C u S O_{4}

is 0.01 M, the emf changed to

E_{2}

.What is the relationship between

E_{1}

E_{2}

Q. The e.m.f of a Daniell cell at

298 K

E_{1}

Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) | C u

When the concentration of

Z n S O_{4}

1.0 M

C u S O_{4}

0.01 M

, the e.m.f changed to

E_{2}

. What is the relationship between

E_{1}

E_{2}

?

Q. The emf of Daniell cell at

298 K

E_{1} Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) | C u

When the concentration of

Z n S O_{4}

1.0 M

C u S O_{4}

0.01 M

, the emf changed to

E_{2}

What is the relation between

E_{1}

E_{2}

?

In the electrochemical cell:

Z n | Z n S O_{4} (0.01 M) ∥ C u S O_{4} (1.0 M) | C u

, the emf of a Daniell cell at

298 K

E_{1}

. When the concentration of

Z n S O_{4}

1.0 M

C u S O_{4}

0.01 M

, the emf changed to

E_{2}

. What is the relations between

E_{1}

E_{2}

Q. In the electrochemical cell:

Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) C u

, the emf of this Daniell cell is

E_{1}

. When the concentration of

Z n S O_{4}

is changed to 1.0 M and that of

C u S O_{4}

changed to 0.01 M, the emf changes to

E_{2}

. From the followings, which one is the relationship between

E_{1}

E_{2}

? (Given, RT/F = 0.059)

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