Question

The EAN of metal atoms in $\left[Fe\right(CO{)}_2\left(N{O}^{+}{)}_2\right]$ and $C{o}_2(CO{)}_8$ respectively are:
(correct answer +2, wrong answer -0.5)

• A. $34,35$
• B. $34,36$
• C. $36,36$
• D. $36,35$

Answer 1

The correct option is C $36,36$

$\text{Oxidation state of Fe in}\left[Fe\right(CO{)}_2\left(N{O}^{+}{)}_2\right]is$:
$x+2\left(0\right)+2=0$
$x=-2$
$soEAN=26+2+8=36$

$\text{Oxidation state of Co in}C{o}_2(CO{)}_8=2x+8(0)=0$
$x=0$
$(CO{)}_{4}Co-Co(CO{)}_4$

Each $Co$ will get one electron by sharing between them.
Hence EAN for both $Co=27+1+8=36$