The earth (mass $= 6 \times 10^{24} k g$ ) revolves around the earth, $R$ being radius of the earth. The acceleration of earth's gravity will be about :

27 \times 10^{39}

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18 \times 10^{25}

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36 \times 10^{21}

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10 \times 10^{28}

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Solution

The correct option is A $10 \times 10^{28}$
Acceleration due to gravity can be calculated as,

$g = \frac{G M}{R^{2}}$

$= \frac{6.6 \times 10^{- 11} \times 6400 \times 10^{3}}{6 \times 10^{24}} m / s^{2}$

$= 9.8 m / s^{2}$

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The earth (mass =6×1024kg ) revolves around the earth, R being radius of the earth. The acceleration of earth's gravity will be about :

The correct option is A 10×1028Acceleration due to gravity can be calculated as, g=GMR2 =6.6×10−11×6400×1036×1024m/s2 =9.8m/s2

The earth (mass $= 6 \times 10^{24} k g$ ) revolves around the earth, $R$ being radius of the earth. The acceleration of earth's gravity will be about :

The correct option is A $10 \times 10^{28}$
Acceleration due to gravity can be calculated as,

$g = \frac{G M}{R^{2}}$

$= \frac{6.6 \times 10^{- 11} \times 6400 \times 10^{3}}{6 \times 10^{24}} m / s^{2}$

$= 9.8 m / s^{2}$