The earth taken out from a pit is evenly spread over a rectangular field of length $80 m$ and width $60 m$ . If the volume of the earth dug is $3696 m^{3}$ . then the field is raised by

75 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

77 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

80 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

85 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $77 c m$
Volume of earth dug out $= 3696 m^{3}$
Length of rectangular field $= 80$ m
width of rectangular field $= 60$ m
$∴$ Height raised
$= \frac{V o l u m e o f e a r t h d u g o u t}{A r e a o f r e c t a n g u l a r p i t} = \frac{3696 m^{3}}{80 m \times 60 m} = \frac{3696}{4800} m = 0.77 m = 77 c m$

Suggest Corrections

Similar questions

Q. A rectangular field is 70 m long and 60 m broad. A well of dimensions 14 m × 8 m × 6 m is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

A field is $80 m$ long and $50 m$ broad. In one corner of field, a pit which is $10 m$ long, $7.5 m$ broad and $8 m$ deep has been dug out. The earth taken out of it is evenly spread over the remaining part of field. Find the rise in level of field.

A field is 80 m long and 50 m broad. In one corner of the field a pit which is 10 m long, 7.5 m broad and 8 m deep has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. If the rise in the level of the field is x(in cm), then x-0.3 =