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Question

The earth's magnetic field at the equator is approximately 0.4×10-4T. What is the earth's dipole moment?Re=6.4×106m.


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Solution

Step 1: Given data

The magnetic field at the equator is B=0.4×10-4T

The radius of the earth is Re=6.4×106m

Absolute permeability of free space μo=4π×10-7H/m

Step 2: Formula used

B=μom4πRe3

Step 3: Calculation of dipole moment:

Let, m be the pole strength of earth's magnet.

Now, the magnetic field is, B=μom4πRe3

m=B×4πRe3μom=0.4×10-410-7×6.4×1063m=1.05×1023Am2

Hence, the dipole moment of the earth is 1.05×1023Am2.


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