The eccentricity of the hyperbola whose asymptotes are 3x+4y=10 and 4x−3y=5 is
A
√3
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B
√2
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C
√5
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D
√6
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Solution
The correct option is B√2 If θ is angle between asymptotes, then θ=tan−1ba ⇒tanθ2=ba ⇒tanπ4=ba
(∵ given lines are perpendicular ) ∴a=b ⇒e=√2 which is a rectangular hyperbola.