The effective atomic number of cobalt in the complex $[C o (N H_{3})_{6}]^{3 +}$ is:

33

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30

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36

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24

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Solution

The correct option is C $36$
$EAN = Z - X + 2 n$
where $Z =$ Atomic number
$X =$ Oxidation state
$n =$ Coordination number
$∴$ For the complex $[C o (N H_{3})_{6}]^{3 +}$ the effective atomic number is
$= 27 - 3 + 12 = 36$

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Similar questions

[C o (N H_{3})_{6}]^{3 +}

E A N

[C o (N H_{3})_{6}]^{+ 3}

(Z = 27)

[C O (N H_{3})_{6}]^{+ 3}

(Z = 30)

[Z n (N H_{3})_{4}] S O_{4}

[C o {(N H_{3})}_{6}] [C d C l_{x}]

[C o (N H_{3})_{6}] C l_{3}

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