The elastic energy stored per unit volume in a stretched wire is

\frac{1}{2} \frac{{(s t r e s s)}}{Y}

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\frac{1}{2} \frac{{(s t r e s s)}^{2}}{Y}

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\frac{1}{2} \frac{{(s t r e s s)}^{2}}{Y^{2}}

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\frac{1}{2} \frac{{(s t r e s s)}}{Y^{2}}

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Solution

The correct option is B $\frac{1}{2} \frac{{(s t r e s s)}^{2}}{Y}$
The elastic energy stored per unit volume in a stretched wire is
$u = \frac{1}{2} \times s t r e s s \times s t r a i n = \frac{{(s t r e s s)}^{2}}{2 Y} (∵ Y = \frac{s t r e s s}{s t r a i n})$

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The elastic energy stored per unit volume in a stretched wire is

The correct option is B 12(stress)2YThe elastic energy stored per unit volume in a stretched wire isu=12×stress×strain=(stress)22Y(∵Y=stressstrain)

The correct option is B $\frac{1}{2} \frac{{(s t r e s s)}^{2}}{Y}$
The elastic energy stored per unit volume in a stretched wire is
$u = \frac{1}{2} \times s t r e s s \times s t r a i n = \frac{{(s t r e s s)}^{2}}{2 Y} (∵ Y = \frac{s t r e s s}{s t r a i n})$