You visited us 1 times! Enjoying our articles? Unlock Full Access!

Torque on a Dipole

The electric ...

Question

The electric dipole moment is:

15.36 \times 10^{- 29} C - m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15.36 \times 10^{- 19} C - m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.68 \times 10^{- 29} C - m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.68 \times 10^{- 19} C - m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $7.68 \times 10^{- 29} C - m$
We know electric dipole moment
$P = q . d$
where q is the magnitude of each charge
d is the distance between them
On putting the values we get
$P = 3.2 \times 10^{- 19} \times 2.44$
$P = 7.68 \times 10^{- 29} C - m$

Suggest Corrections

Similar questions

+ 3.2 \times 10^{- 19} C

- 3.2 \times 10^{- 19} C

2.4 o A

4 \times 10^{5} volt/m

6.48 \times 10^{- 19} C, 12.82 \times 10^{- 19} C, 19.3 \times 10^{- 19} C, 8.02 \times 10^{- 19} C, 25.62 \times 10^{- 19} C, 16.04 \times 10^{- 19} C,

3.2 \times 10^{- 19} C

- 3.2 \times 10^{- 19} C

2.4 \times 10^{- 10} m

4 \times 10^{5} V m^{- 1} .

180^{\circ}

n \times 10^{- 23} J

n

\to p = (3 i + 4 j) \times 10^{- 30} C - m

\to E = 4000^i (N / C)

(- 4^i + 3^j) \times 10^{- 30} C - m

1000 V/m

10^{- 29} C \cdot m .

Join BYJU'S Learning Program