The electric field components in the given figure are Ex=αx1/2,Ey=Ez=0 in which α=800NC−1m−1/2. The charge within the cube is, if net flux through the cube is 1.05Nm2C−1(assume a=0.1m)
A
9.27×10−12C
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B
9.27×1012C
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C
6.97×10−12C
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D
6.97×1012C
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Solution
The correct option is A9.27×10−12C By Gauss's law q=ϕε0=1.05×8.854×10−12C=9.27×10−12C